This post is an aside. Here I show how to prove Kepler's third law of planetary motion from what we have done so far. Nothing which follows depends on it, and if you choose to skip this post then you will lose nothing of substance from the series on Orbital Mechanics.

Kepler's third law states that

*the square of the period of a planetary orbit is proportional to the cube of its distance from the Sun*.

In one orbit, the orbiting body travels a distance equal to the circumference of the circle with radius r. This distance is 2πr. So the time taken to travel this distance, or the period of the orbit in seconds, P, is given by

P = 2πr / V

_{C}
Taking the square of both sides gives

P² = 4π²r² / V

_{C}²
Now from our last post we know that

V

_{C}² = GM/r
Putting this into the equation for the period squared gives

P² = 4π²r² / (GM/r)

which simplifies to

P² = 4π²r

^{3}/ GM
Now if this equation is applied to planets orbiting the Sun, then

*the square of period of the orbit*, P², is directly proportional to*the cube of the distance from the Sun*, r^{3}. So we have proved Kepler's third law.
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